Base | Representation |
---|---|
bin | 100100011111111001110100… |
… | …0110110110001100110000111 |
3 | 1120002201111222212101011110112 |
4 | 1020333303220312301212013 |
5 | 314034441330230130224 |
6 | 3054445344510543235 |
7 | 124423446426164123 |
oct | 11077635066614607 |
9 | 1502644885334415 |
10 | 321044122114439 |
11 | 93327058370039 |
12 | 30010602b07b1b |
13 | 10a1a43ba427b9 |
14 | 593c892d28583 |
15 | 271b16378a30e |
hex | 123fce8db1987 |
321044122114439 has 2 divisors, whose sum is σ = 321044122114440. Its totient is φ = 321044122114438.
The previous prime is 321044122114279. The next prime is 321044122114477. The reversal of 321044122114439 is 934411221440123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 321044122114439 - 228 = 321043853678983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 321044122114396 and 321044122114405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (321044122144439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160522061057219 + 160522061057220.
It is an arithmetic number, because the mean of its divisors is an integer number (160522061057220).
Almost surely, 2321044122114439 is an apocalyptic number.
321044122114439 is a deficient number, since it is larger than the sum of its proper divisors (1).
321044122114439 is an equidigital number, since it uses as much as digits as its factorization.
321044122114439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 165888, while the sum is 41.
The spelling of 321044122114439 in words is "three hundred twenty-one trillion, forty-four billion, one hundred twenty-two million, one hundred fourteen thousand, four hundred thirty-nine".
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