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32111103113 is a prime number
BaseRepresentation
bin11101111001111110…
…001000110010001001
310001212212201001102022
4131321332020302021
51011230420244423
622430204214225
72214512605265
oct357176106211
9101785631368
1032111103113
1112688976051
126281b3a375
13304986c93b
1417a89850a5
15c7e135dc8
hex779f88c89

32111103113 has 2 divisors, whose sum is σ = 32111103114. Its totient is φ = 32111103112.

The previous prime is 32111103109. The next prime is 32111103131. The reversal of 32111103113 is 31130111123.

Together with next prime (32111103131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30035662864 + 2075440249 = 173308^2 + 45557^2 .

It is a cyclic number.

It is not a de Polignac number, because 32111103113 - 22 = 32111103109 is a prime.

It is a super-2 number, since 2×321111031132 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 32111103091 and 32111103100.

It is not a weakly prime, because it can be changed into another prime (32111103103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16055551556 + 16055551557.

It is an arithmetic number, because the mean of its divisors is an integer number (16055551557).

Almost surely, 232111103113 is an apocalyptic number.

It is an amenable number.

32111103113 is a deficient number, since it is larger than the sum of its proper divisors (1).

32111103113 is an equidigital number, since it uses as much as digits as its factorization.

32111103113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 32111103113 its reverse (31130111123), we get a palindrome (63241214236).

The spelling of 32111103113 in words is "thirty-two billion, one hundred eleven million, one hundred three thousand, one hundred thirteen".