32111103131 has 2 divisors, whose sum is σ = 32111103132. Its totient is φ = 32111103130.

The previous prime is 32111103113. The next prime is 32111103133. The reversal of 32111103131 is 13130111123.

Together with previous prime (32111103113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 32111103131 - 2¹⁴ = 32111086747 is a prime.

It is a super-2 number, since 2×32111103131² (a number of 22 digits) contains 22 as substring.

Together with 32111103133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (32111103133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16055551565 + 16055551566.

It is an arithmetic number, because the mean of its divisors is an integer number (16055551566).

Almost surely, 2^32111103131 is an apocalyptic number.

32111103131 is a deficient number, since it is larger than the sum of its proper divisors (1).

32111103131 is an equidigital number, since it uses as much as digits as its factorization.

32111103131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 32111103131 its reverse (13130111123), we get a palindrome (45241214254).

The spelling of 32111103131 in words is "thirty-two billion, one hundred eleven million, one hundred three thousand, one hundred thirty-one".