3211121133133 has 4 divisors (see below), whose sum is σ = 3219593748640. Its totient is φ = 3202648517628.

The previous prime is 3211121133131. The next prime is 3211121133137. The reversal of 3211121133133 is 3313311211123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3211121133133 - 2¹ = 3211121133131 is a prime.

It is a super-2 number, since 2×3211121133133² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3211121133098 and 3211121133107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3211121133131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4236307185 + ... + 4236307942.

It is an arithmetic number, because the mean of its divisors is an integer number (804898437160).

Almost surely, 2^{3211121133133} is an apocalyptic number.

It is an amenable number.

3211121133133 is a deficient number, since it is larger than the sum of its proper divisors (8472615507).

3211121133133 is an equidigital number, since it uses as much as digits as its factorization.

3211121133133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8472615506.

The product of its digits is 972, while the sum is 25.

Adding to 3211121133133 its reverse (3313311211123), we get a palindrome (6524432344256).

The spelling of 3211121133133 in words is "three trillion, two hundred eleven billion, one hundred twenty-one million, one hundred thirty-three thousand, one hundred thirty-three".