Base | Representation |
---|---|
bin | 101110101110100110010… |
… | …101100001011110101011 |
3 | 102100222111020221001001212 |
4 | 232232212111201132223 |
5 | 410102344043330443 |
6 | 10455101234303335 |
7 | 450665553050045 |
oct | 56564625413653 |
9 | 12328436831055 |
10 | 3211131230123 |
11 | 1028918957913 |
12 | 43a409427b4b |
13 | 1a3a6800307b |
14 | b15c3488a95 |
15 | 587e002a618 |
hex | 2eba65617ab |
3211131230123 has 2 divisors, whose sum is σ = 3211131230124. Its totient is φ = 3211131230122.
The previous prime is 3211131230089. The next prime is 3211131230143. The reversal of 3211131230123 is 3210321311123.
3211131230123 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3211131230123 - 232 = 3206836262827 is a prime.
It is a super-3 number, since 3×32111312301233 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (3211131230143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1605565615061 + 1605565615062.
It is an arithmetic number, because the mean of its divisors is an integer number (1605565615062).
Almost surely, 23211131230123 is an apocalyptic number.
3211131230123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3211131230123 is an equidigital number, since it uses as much as digits as its factorization.
3211131230123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 3211131230123 its reverse (3210321311123), we get a palindrome (6421452541246).
The spelling of 3211131230123 in words is "three trillion, two hundred eleven billion, one hundred thirty-one million, two hundred thirty thousand, one hundred twenty-three".
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