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3211131230089 is a prime number
BaseRepresentation
bin101110101110100110010…
…101100001011110001001
3102100222111020221001000121
4232232212111201132021
5410102344043330324
610455101234303241
7450665553046666
oct56564625413611
912328436831017
103211131230089
111028918957892
1243a409427b21
131a3a68003053
14b15c3488a6d
15587e002a5e4
hex2eba6561789

3211131230089 has 2 divisors, whose sum is σ = 3211131230090. Its totient is φ = 3211131230088.

The previous prime is 3211131230053. The next prime is 3211131230123. The reversal of 3211131230089 is 9800321311123.

It is an a-pointer prime, because the next prime (3211131230123) can be obtained adding 3211131230089 to its sum of digits (34).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2802918852864 + 408212377225 = 1674192^2 + 638915^2 .

It is a cyclic number.

It is not a de Polignac number, because 3211131230089 - 237 = 3073692276617 is a prime.

It is a super-3 number, since 3×32111312300893 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (3211131030089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1605565615044 + 1605565615045.

It is an arithmetic number, because the mean of its divisors is an integer number (1605565615045).

Almost surely, 23211131230089 is an apocalyptic number.

It is an amenable number.

3211131230089 is a deficient number, since it is larger than the sum of its proper divisors (1).

3211131230089 is an equidigital number, since it uses as much as digits as its factorization.

3211131230089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 34.

The spelling of 3211131230089 in words is "three trillion, two hundred eleven billion, one hundred thirty-one million, two hundred thirty thousand, eighty-nine".