Base | Representation |
---|---|
bin | 101110101110100110011… |
… | …000111101010000011010 |
3 | 102100222111022121202220212 |
4 | 232232212120331100122 |
5 | 410102344311132310 |
6 | 10455101305451122 |
7 | 450665563516415 |
oct | 56564630752032 |
9 | 12328438552825 |
10 | 3211132130330 |
11 | 1028919412193 |
12 | 43a4097a0aa2 |
13 | 1a3a68259a37 |
14 | b15c3640b7c |
15 | 587e0157205 |
hex | 2eba663d41a |
3211132130330 has 16 divisors (see below), whose sum is σ = 5966490668544. Its totient is φ = 1243018889040.
The previous prime is 3211132130183. The next prime is 3211132130333. The reversal of 3211132130330 is 330312311123.
It is a super-3 number, since 3×32111321303303 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 3211132130296 and 3211132130305.
It is not an unprimeable number, because it can be changed into a prime (3211132130333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5179245062 + ... + 5179245681.
It is an arithmetic number, because the mean of its divisors is an integer number (372905666784).
Almost surely, 23211132130330 is an apocalyptic number.
3211132130330 is a deficient number, since it is larger than the sum of its proper divisors (2755358538214).
3211132130330 is a wasteful number, since it uses less digits than its factorization.
3211132130330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10358490781.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 3211132130330 its reverse (330312311123), we get a palindrome (3541444441453).
The spelling of 3211132130330 in words is "three trillion, two hundred eleven billion, one hundred thirty-two million, one hundred thirty thousand, three hundred thirty".
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