321114899057 has 2 divisors, whose sum is σ = 321114899058. Its totient is φ = 321114899056.

The previous prime is 321114899041. The next prime is 321114899107. The reversal of 321114899057 is 750998411123.

It is an a-pointer prime, because the next prime (321114899107) can be obtained adding 321114899057 to its sum of digits (50).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 194339023921 + 126775875136 = 440839^2 + 356056^2 .

It is an emirp because it is prime and its reverse (750998411123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 321114899057 - 2⁴ = 321114899041 is a prime.

It is a super-2 number, since 2×321114899057² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 321114898996 and 321114899014.

It is not a weakly prime, because it can be changed into another prime (321114892057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160557449528 + 160557449529.

It is an arithmetic number, because the mean of its divisors is an integer number (160557449529).

Almost surely, 2^321114899057 is an apocalyptic number.

It is an amenable number.

321114899057 is a deficient number, since it is larger than the sum of its proper divisors (1).

321114899057 is an equidigital number, since it uses as much as digits as its factorization.

321114899057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 50.

The spelling of 321114899057 in words is "three hundred twenty-one billion, one hundred fourteen million, eight hundred ninety-nine thousand, fifty-seven".