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321131011133 is a prime number
BaseRepresentation
bin1001010110001001110…
…01100101110000111101
31010200220011122121121002
410223010321211300331
520230134014324013
6403305304020045
732125632361652
oct4530471456075
91120804577532
10321131011133
111142110a1769
12522a2161625
13243899244aa
1411785719c29
158547889358
hex4ac4e65c3d

321131011133 has 2 divisors, whose sum is σ = 321131011134. Its totient is φ = 321131011132.

The previous prime is 321131011127. The next prime is 321131011163. The reversal of 321131011133 is 331110131123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 240848322169 + 80282688964 = 490763^2 + 283342^2 .

It is an emirp because it is prime and its reverse (331110131123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 321131011133 - 212 = 321131007037 is a prime.

It is a super-2 number, since 2×3211310111332 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (321131011163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565505566 + 160565505567.

It is an arithmetic number, because the mean of its divisors is an integer number (160565505567).

Almost surely, 2321131011133 is an apocalyptic number.

It is an amenable number.

321131011133 is a deficient number, since it is larger than the sum of its proper divisors (1).

321131011133 is an equidigital number, since it uses as much as digits as its factorization.

321131011133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 321131011133 its reverse (331110131123), we get a palindrome (652241142256).

The spelling of 321131011133 in words is "three hundred twenty-one billion, one hundred thirty-one million, eleven thousand, one hundred thirty-three".