Base | Representation |
---|---|
bin | 1001010110001001110… |
… | …10010110100111010111 |
3 | 1010200220012000210001211 |
4 | 10223010322112213113 |
5 | 20230134042224343 |
6 | 403305312202251 |
7 | 32125634154214 |
oct | 4530472264727 |
9 | 1120805023054 |
10 | 321131211223 |
11 | 114211219029 |
12 | 522a2239387 |
13 | 243899945a4 |
14 | 1178576cb0b |
15 | 85478c879d |
hex | 4ac4e969d7 |
321131211223 has 2 divisors, whose sum is σ = 321131211224. Its totient is φ = 321131211222.
The previous prime is 321131211173. The next prime is 321131211253. The reversal of 321131211223 is 322112131123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 321131211223 - 237 = 183692257751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 321131211194 and 321131211203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (321131211253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565605611 + 160565605612.
It is an arithmetic number, because the mean of its divisors is an integer number (160565605612).
Almost surely, 2321131211223 is an apocalyptic number.
321131211223 is a deficient number, since it is larger than the sum of its proper divisors (1).
321131211223 is an equidigital number, since it uses as much as digits as its factorization.
321131211223 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 432, while the sum is 22.
Adding to 321131211223 its reverse (322112131123), we get a palindrome (643243342346).
The spelling of 321131211223 in words is "three hundred twenty-one billion, one hundred thirty-one million, two hundred eleven thousand, two hundred twenty-three".
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