Base | Representation |
---|---|
bin | 1110100110100111010110… |
… | …01111000111110010110011 |
3 | 11012200222120200202110002111 |
4 | 13103103223033013302303 |
5 | 13202120133230132424 |
6 | 152144321543430151 |
7 | 6523045050120121 |
oct | 723235317076263 |
9 | 135628520673074 |
10 | 32113122114739 |
11 | a26110a278a66 |
12 | 37278a3755357 |
13 | 14bc33cc6c393 |
14 | 7d03d7932911 |
15 | 3aa509015194 |
hex | 1d34eb3c7cb3 |
32113122114739 has 2 divisors, whose sum is σ = 32113122114740. Its totient is φ = 32113122114738.
The previous prime is 32113122114719. The next prime is 32113122114761. The reversal of 32113122114739 is 93741122131123.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (93741122131123) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32113122114739 - 27 = 32113122114611 is a prime.
It is a super-2 number, since 2×321131221147392 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (32113122114719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056561057369 + 16056561057370.
It is an arithmetic number, because the mean of its divisors is an integer number (16056561057370).
Almost surely, 232113122114739 is an apocalyptic number.
32113122114739 is a deficient number, since it is larger than the sum of its proper divisors (1).
32113122114739 is an equidigital number, since it uses as much as digits as its factorization.
32113122114739 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54432, while the sum is 40.
The spelling of 32113122114739 in words is "thirty-two trillion, one hundred thirteen billion, one hundred twenty-two million, one hundred fourteen thousand, seven hundred thirty-nine".
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