Base | Representation |
---|---|
bin | 1110100110100111010111… |
… | …01101001101000010000111 |
3 | 11012200222121020121002100102 |
4 | 13103103223231031002013 |
5 | 13202120142240004034 |
6 | 152144322424434315 |
7 | 6523045204132541 |
oct | 723235355150207 |
9 | 135628536532312 |
10 | 32113130000519 |
11 | a261113774737 |
12 | 37278a631899b |
13 | 14bc3417a0819 |
14 | 7d03d89c6691 |
15 | 3aa509a7197e |
hex | 1d34ebb4d087 |
32113130000519 has 2 divisors, whose sum is σ = 32113130000520. Its totient is φ = 32113130000518.
The previous prime is 32113130000489. The next prime is 32113130000537. The reversal of 32113130000519 is 91500003131123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 32113130000519 - 228 = 32112861565063 is a prime.
It is a super-2 number, since 2×321131300005192 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32113130000491 and 32113130000500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32113130000599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056565000259 + 16056565000260.
It is an arithmetic number, because the mean of its divisors is an integer number (16056565000260).
Almost surely, 232113130000519 is an apocalyptic number.
32113130000519 is a deficient number, since it is larger than the sum of its proper divisors (1).
32113130000519 is an equidigital number, since it uses as much as digits as its factorization.
32113130000519 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2430, while the sum is 29.
The spelling of 32113130000519 in words is "thirty-two trillion, one hundred thirteen billion, one hundred thirty million, five hundred nineteen", and thus it is an aban number.
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