32113130001011 has 2 divisors, whose sum is σ = 32113130001012. Its totient is φ = 32113130001010.

The previous prime is 32113130000953. The next prime is 32113130001013. The reversal of 32113130001011 is 11010003131123.

It is a strong prime.

It is an emirp because it is prime and its reverse (11010003131123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32113130001011 - 2²⁶ = 32113062892147 is a prime.

It is a super-2 number, since 2×32113130001011² (a number of 28 digits) contains 22 as substring.

Together with 32113130001013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (32113130001013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056565000505 + 16056565000506.

It is an arithmetic number, because the mean of its divisors is an integer number (16056565000506).

Almost surely, 2^{32113130001011} is an apocalyptic number.

32113130001011 is a deficient number, since it is larger than the sum of its proper divisors (1).

32113130001011 is an equidigital number, since it uses as much as digits as its factorization.

32113130001011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 32113130001011 its reverse (11010003131123), we get a palindrome (43123133132134).

The spelling of 32113130001011 in words is "thirty-two trillion, one hundred thirteen billion, one hundred thirty million, one thousand, eleven".