3211314103 has 2 divisors, whose sum is σ = 3211314104. Its totient is φ = 3211314102.

The previous prime is 3211314031. The next prime is 3211314137. The reversal of 3211314103 is 3014131123.

Together with previous prime (3211314031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (3014131123) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3211314103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3211314503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1605657051 + 1605657052.

It is an arithmetic number, because the mean of its divisors is an integer number (1605657052).

Almost surely, 2^3211314103 is an apocalyptic number.

3211314103 is a deficient number, since it is larger than the sum of its proper divisors (1).

3211314103 is an equidigital number, since it uses as much as digits as its factorization.

3211314103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 3211314103 is about 56668.4577432631. The cubic root of 3211314103 is about 1475.3472862999.

Adding to 3211314103 its reverse (3014131123), we get a palindrome (6225445226).

The spelling of 3211314103 in words is "three billion, two hundred eleven million, three hundred fourteen thousand, one hundred three".