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321131412353 is a prime number
BaseRepresentation
bin1001010110001001110…
…11000111101110000001
31010200220012101222222002
410223010323013232001
520230134120143403
6403305320353345
732125635652463
oct4530473075601
91120805358862
10321131412353
11114211346154
12522a2315855
1324389a34cbb
14117857c2133
158547918188
hex4ac4ec7b81

321131412353 has 2 divisors, whose sum is σ = 321131412354. Its totient is φ = 321131412352.

The previous prime is 321131412331. The next prime is 321131412361. The reversal of 321131412353 is 353214131123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 283015488064 + 38115924289 = 531992^2 + 195233^2 .

It is a cyclic number.

It is not a de Polignac number, because 321131412353 - 210 = 321131411329 is a prime.

It is not a weakly prime, because it can be changed into another prime (321131402353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160565706176 + 160565706177.

It is an arithmetic number, because the mean of its divisors is an integer number (160565706177).

Almost surely, 2321131412353 is an apocalyptic number.

It is an amenable number.

321131412353 is a deficient number, since it is larger than the sum of its proper divisors (1).

321131412353 is an equidigital number, since it uses as much as digits as its factorization.

321131412353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480, while the sum is 29.

Adding to 321131412353 its reverse (353214131123), we get a palindrome (674345543476).

The spelling of 321131412353 in words is "three hundred twenty-one billion, one hundred thirty-one million, four hundred twelve thousand, three hundred fifty-three".