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321132053113 is a prime number
BaseRepresentation
bin1001010110001001111…
…01100100001001111001
31010200220020121112220221
410223010331210021321
520230134301144423
6403305342220041
732125644261544
oct4530475441171
91120806545827
10321132053113
11114211743603
12522a2584621
1324389bca851
141178590b85b
1585479e2e5d
hex4ac4f64279

321132053113 has 2 divisors, whose sum is σ = 321132053114. Its totient is φ = 321132053112.

The previous prime is 321132053093. The next prime is 321132053119. The reversal of 321132053113 is 311350231123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 316644794944 + 4487258169 = 562712^2 + 66987^2 .

It is an emirp because it is prime and its reverse (311350231123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 321132053113 - 237 = 183693099641 is a prime.

It is not a weakly prime, because it can be changed into another prime (321132053119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160566026556 + 160566026557.

It is an arithmetic number, because the mean of its divisors is an integer number (160566026557).

Almost surely, 2321132053113 is an apocalyptic number.

It is an amenable number.

321132053113 is a deficient number, since it is larger than the sum of its proper divisors (1).

321132053113 is an equidigital number, since it uses as much as digits as its factorization.

321132053113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 321132053113 its reverse (311350231123), we get a palindrome (632482284236).

The spelling of 321132053113 in words is "three hundred twenty-one billion, one hundred thirty-two million, fifty-three thousand, one hundred thirteen".