Base | Representation |
---|---|
bin | 101110101111100000001… |
… | …000111111000110000011 |
3 | 102101001222211202120112121 |
4 | 232233200020333012003 |
5 | 410111340330201313 |
6 | 10455341400305111 |
7 | 451031600124622 |
oct | 56574010770603 |
9 | 12331884676477 |
10 | 3212101022083 |
11 | 1029276318978 |
12 | 43a63a172197 |
13 | 1a3b90bc4675 |
14 | b16761b16b9 |
15 | 5884a24128d |
hex | 2ebe023f183 |
3212101022083 has 2 divisors, whose sum is σ = 3212101022084. Its totient is φ = 3212101022082.
The previous prime is 3212101022077. The next prime is 3212101022101. The reversal of 3212101022083 is 3802201012123.
3212101022083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3212101022083 is a prime.
It is not a weakly prime, because it can be changed into another prime (3212101022023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606050511041 + 1606050511042.
It is an arithmetic number, because the mean of its divisors is an integer number (1606050511042).
Almost surely, 23212101022083 is an apocalyptic number.
3212101022083 is a deficient number, since it is larger than the sum of its proper divisors (1).
3212101022083 is an equidigital number, since it uses as much as digits as its factorization.
3212101022083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
The spelling of 3212101022083 in words is "three trillion, two hundred twelve billion, one hundred one million, twenty-two thousand, eighty-three".
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