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3212299233149 is a prime number
BaseRepresentation
bin101110101111101011111…
…101000110011101111101
3102101002111122201202000012
4232233223331012131331
5410112242100430044
610455413200513005
7451036524651506
oct56575375063575
912332448652005
103212299233149
111029368199876
1243a69461b765
131a3bc2ca3616
14b1694649bad
155885c84559e
hex2ebebf4677d

3212299233149 has 2 divisors, whose sum is σ = 3212299233150. Its totient is φ = 3212299233148.

The previous prime is 3212299233139. The next prime is 3212299233197. The reversal of 3212299233149 is 9413329922123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2633132572249 + 579166660900 = 1622693^2 + 761030^2 .

It is a cyclic number.

It is not a de Polignac number, because 3212299233149 - 24 = 3212299233133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3212299233097 and 3212299233106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3212299233139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606149616574 + 1606149616575.

It is an arithmetic number, because the mean of its divisors is an integer number (1606149616575).

Almost surely, 23212299233149 is an apocalyptic number.

It is an amenable number.

3212299233149 is a deficient number, since it is larger than the sum of its proper divisors (1).

3212299233149 is an equidigital number, since it uses as much as digits as its factorization.

3212299233149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1259712, while the sum is 50.

The spelling of 3212299233149 in words is "three trillion, two hundred twelve billion, two hundred ninety-nine million, two hundred thirty-three thousand, one hundred forty-nine".