Base | Representation |
---|---|
bin | 100100100001010000100001… |
… | …0101001101000001100010111 |
3 | 1120010101022120202220002011001 |
4 | 1021002201002221220030113 |
5 | 314101014134411224343 |
6 | 3055111100154524131 |
7 | 124443060410662462 |
oct | 11102410251501427 |
9 | 1503338522802131 |
10 | 321230312211223 |
11 | 93399012871588 |
12 | 30040705736647 |
13 | 10a31b71c505bc |
14 | 59478b6c982d9 |
15 | 2720e0e62b44d |
hex | 1242842a68317 |
321230312211223 has 2 divisors, whose sum is σ = 321230312211224. Its totient is φ = 321230312211222.
The previous prime is 321230312211209. The next prime is 321230312211269. The reversal of 321230312211223 is 322112213032123.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 321230312211223 - 241 = 319031288955671 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 321230312211191 and 321230312211200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (321230312211293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160615156105611 + 160615156105612.
It is an arithmetic number, because the mean of its divisors is an integer number (160615156105612).
Almost surely, 2321230312211223 is an apocalyptic number.
321230312211223 is a deficient number, since it is larger than the sum of its proper divisors (1).
321230312211223 is an equidigital number, since it uses as much as digits as its factorization.
321230312211223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 321230312211223 its reverse (322112213032123), we get a palindrome (643342525243346).
The spelling of 321230312211223 in words is "three hundred twenty-one trillion, two hundred thirty billion, three hundred twelve million, two hundred eleven thousand, two hundred twenty-three".
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