3212452433 has 2 divisors, whose sum is σ = 3212452434. Its totient is φ = 3212452432.

The previous prime is 3212452403. The next prime is 3212452457. The reversal of 3212452433 is 3342542123.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3127941184 + 84511249 = 55928^2 + 9193^2 .

It is an emirp because it is prime and its reverse (3342542123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3212452433 - 2¹⁰ = 3212451409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3212452396 and 3212452405.

It is not a weakly prime, because it can be changed into another prime (3212452403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606226216 + 1606226217.

It is an arithmetic number, because the mean of its divisors is an integer number (1606226217).

Almost surely, 2^3212452433 is an apocalyptic number.

It is an amenable number.

3212452433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3212452433 is an equidigital number, since it uses as much as digits as its factorization.

3212452433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17280, while the sum is 29.

The square root of 3212452433 is about 56678.5006241344. The cubic root of 3212452433 is about 1475.5215901957.

Adding to 3212452433 its reverse (3342542123), we get a palindrome (6554994556).

The spelling of 3212452433 in words is "three billion, two hundred twelve million, four hundred fifty-two thousand, four hundred thirty-three".