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3212454454813 is a prime number
BaseRepresentation
bin101110101111110101001…
…101001110011000011101
3102101002220110210211002201
4232233311031032120131
5410113101320023223
610455440423451501
7451043421220012
oct56576515163035
912332813724081
103212454454813
11102943787813a
1243a7185b6b91
131a3c191b0166
14b16ab0d3709
155886b2a6ead
hex2ebf534e61d

3212454454813 has 2 divisors, whose sum is σ = 3212454454814. Its totient is φ = 3212454454812.

The previous prime is 3212454454799. The next prime is 3212454454823. The reversal of 3212454454813 is 3184544542123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1778910402564 + 1433544052249 = 1333758^2 + 1197307^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3212454454813 is a prime.

It is a super-3 number, since 3×32124544548133 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3212454454823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606227227406 + 1606227227407.

It is an arithmetic number, because the mean of its divisors is an integer number (1606227227407).

Almost surely, 23212454454813 is an apocalyptic number.

It is an amenable number.

3212454454813 is a deficient number, since it is larger than the sum of its proper divisors (1).

3212454454813 is an equidigital number, since it uses as much as digits as its factorization.

3212454454813 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1843200, while the sum is 46.

Adding to 3212454454813 its reverse (3184544542123), we get a palindrome (6396998996936).

The spelling of 3212454454813 in words is "three trillion, two hundred twelve billion, four hundred fifty-four million, four hundred fifty-four thousand, eight hundred thirteen".