32125140127 has 2 divisors, whose sum is σ = 32125140128. Its totient is φ = 32125140126.

The previous prime is 32125140119. The next prime is 32125140163. The reversal of 32125140127 is 72104152123.

It is a weak prime.

It is an emirp because it is prime and its reverse (72104152123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32125140127 - 2³ = 32125140119 is a prime.

It is a super-3 number, since 3×32125140127³ (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 32125140095 and 32125140104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32125146127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16062570063 + 16062570064.

It is an arithmetic number, because the mean of its divisors is an integer number (16062570064).

Almost surely, 2^32125140127 is an apocalyptic number.

32125140127 is a deficient number, since it is larger than the sum of its proper divisors (1).

32125140127 is an equidigital number, since it uses as much as digits as its factorization.

32125140127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 28.

The spelling of 32125140127 in words is "thirty-two billion, one hundred twenty-five million, one hundred forty thousand, one hundred twenty-seven".