Base | Representation |
---|---|
bin | 1110100110111101111001… |
… | …11101000110010101100010 |
3 | 11012202010211112220012010011 |
4 | 13103132330331012111202 |
5 | 13202314433004241010 |
6 | 152154043245155134 |
7 | 6523654106046640 |
oct | 723367475062542 |
9 | 135663745805104 |
10 | 32125230540130 |
11 | a2662631561a2 |
12 | 372a10285baaa |
13 | 14c051c707630 |
14 | 7d0c25ad6190 |
15 | 3aa9b7051a8a |
hex | 1d37bcf46562 |
32125230540130 has 64 divisors (see below), whose sum is σ = 71170863160320. Its totient is φ = 10166945693184.
The previous prime is 32125230540127. The next prime is 32125230540157. The reversal of 32125230540130 is 3104503252123.
It is a super-3 number, since 3×321252305401303 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32125230540092 and 32125230540101.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 66223822 + ... + 66707158.
It is an arithmetic number, because the mean of its divisors is an integer number (1112044736880).
Almost surely, 232125230540130 is an apocalyptic number.
32125230540130 is an abundant number, since it is smaller than the sum of its proper divisors (39045632620190).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
32125230540130 is a wasteful number, since it uses less digits than its factorization.
32125230540130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 556403.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 32125230540130 its reverse (3104503252123), we get a palindrome (35229733792253).
The spelling of 32125230540130 in words is "thirty-two trillion, one hundred twenty-five billion, two hundred thirty million, five hundred forty thousand, one hundred thirty".
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