Base | Representation |
---|---|
bin | 11101111011001010… |
… | …000010101011011011 |
3 | 10001221021010222020222 |
4 | 131323022002223123 |
5 | 1011301014013201 |
6 | 22432154510255 |
7 | 2215144000622 |
oct | 357312025333 |
9 | 101837128228 |
10 | 32131001051 |
11 | 12699126726 |
12 | 628873538b |
13 | 3050a18776 |
14 | 17ab4846b9 |
15 | c80c6691b |
hex | 77b282adb |
32131001051 has 2 divisors, whose sum is σ = 32131001052. Its totient is φ = 32131001050.
The previous prime is 32131001047. The next prime is 32131001053. The reversal of 32131001051 is 15010013123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 32131001051 - 22 = 32131001047 is a prime.
Together with 32131001053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (32131001053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065500525 + 16065500526.
It is an arithmetic number, because the mean of its divisors is an integer number (16065500526).
Almost surely, 232131001051 is an apocalyptic number.
32131001051 is a deficient number, since it is larger than the sum of its proper divisors (1).
32131001051 is an equidigital number, since it uses as much as digits as its factorization.
32131001051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 32131001051 its reverse (15010013123), we get a palindrome (47141014174).
The spelling of 32131001051 in words is "thirty-two billion, one hundred thirty-one million, one thousand, fifty-one".
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