Base | Representation |
---|---|
bin | 101110110000100001100… |
… | …010000110111110010101 |
3 | 102101011211022011021112221 |
4 | 232300201202012332111 |
5 | 410121112210030442 |
6 | 10500042311142341 |
7 | 451101021302335 |
oct | 56604142067625 |
9 | 12334738137487 |
10 | 3213198126997 |
11 | 1029789636051 |
12 | 43a8a56749b1 |
13 | 1a40072a0681 |
14 | b173bb990c5 |
15 | 588b1704467 |
hex | 2ec21886f95 |
3213198126997 has 2 divisors, whose sum is σ = 3213198126998. Its totient is φ = 3213198126996.
The previous prime is 3213198126953. The next prime is 3213198127019. The reversal of 3213198126997 is 7996218913123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2375325181681 + 837872945316 = 1541209^2 + 915354^2 .
It is a cyclic number.
It is not a de Polignac number, because 3213198126997 - 215 = 3213198094229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3213198136997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606599063498 + 1606599063499.
It is an arithmetic number, because the mean of its divisors is an integer number (1606599063499).
Almost surely, 23213198126997 is an apocalyptic number.
It is an amenable number.
3213198126997 is a deficient number, since it is larger than the sum of its proper divisors (1).
3213198126997 is an equidigital number, since it uses as much as digits as its factorization.
3213198126997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8817984, while the sum is 61.
The spelling of 3213198126997 in words is "three trillion, two hundred thirteen billion, one hundred ninety-eight million, one hundred twenty-six thousand, nine hundred ninety-seven".
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