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321322023131 is a prime number
BaseRepresentation
bin1001010110100000100…
…10001111100011011011
31010201101111002000210112
410223100102033203123
520231031414220011
6403340250034535
732133442063154
oct4532022174333
91121344060715
10321322023131
111142a99a591a
1252336118a4b
13243ba382745
14117a2c3c92b
15855951a58b
hex4ad048f8db

321322023131 has 2 divisors, whose sum is σ = 321322023132. Its totient is φ = 321322023130.

The previous prime is 321322023119. The next prime is 321322023133. The reversal of 321322023131 is 131320223123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 321322023131 - 218 = 321321760987 is a prime.

It is a super-2 number, since 2×3213220231312 (a number of 24 digits) contains 22 as substring.

Together with 321322023133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 321322023097 and 321322023106.

It is not a weakly prime, because it can be changed into another prime (321322023133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160661011565 + 160661011566.

It is an arithmetic number, because the mean of its divisors is an integer number (160661011566).

Almost surely, 2321322023131 is an apocalyptic number.

321322023131 is a deficient number, since it is larger than the sum of its proper divisors (1).

321322023131 is an equidigital number, since it uses as much as digits as its factorization.

321322023131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 321322023131 its reverse (131320223123), we get a palindrome (452642246254).

The spelling of 321322023131 in words is "three hundred twenty-one billion, three hundred twenty-two million, twenty-three thousand, one hundred thirty-one".