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32132312130000 = 243544126123831
BaseRepresentation
bin1110100111001011000110…
…00011001110000111010000
311012202211010002011020011110
413103211203003032013100
513202423433401130000
6152201214100213320
76524324435423355
oct723454303160720
9135684102136143
1032132312130000
11a269267567505
12372b55a39a240
1314c10aa8a94b4
147d12d841062c
153aac7dad5850
hex1d39630ce1d0

32132312130000 has 200 divisors, whose sum is σ = 106257328220736. Its totient is φ = 8359625600000.

The previous prime is 32132312129917. The next prime is 32132312130001. The reversal of 32132312130000 is 3121323123.

It is a tau number, because it is divible by the number of its divisors (200).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32132312130001) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 11831916 + ... + 14291915.

Almost surely, 232132312130000 is an apocalyptic number.

32132312130000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

32132312130000 is an abundant number, since it is smaller than the sum of its proper divisors (74125016090736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

32132312130000 is a wasteful number, since it uses less digits than its factorization.

32132312130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26123903 (or 26123882 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 32132312130000 its reverse (3121323123), we get a palindrome (32135433453123).

The spelling of 32132312130000 in words is "thirty-two trillion, one hundred thirty-two billion, three hundred twelve million, one hundred thirty thousand".