Base | Representation |
---|---|
bin | 101110110000101000010… |
… | …100111000111101010110 |
3 | 102101012010020121211011212 |
4 | 232300220110320331112 |
5 | 410121330344232410 |
6 | 10500101502101422 |
7 | 451103604131546 |
oct | 56605024707526 |
9 | 12335106554155 |
10 | 3213312102230 |
11 | 1029837a0235a |
12 | 43a91787a872 |
13 | 1a4024a98239 |
14 | b174cd87326 |
15 | 588bb719b05 |
hex | 2ec28538f56 |
3213312102230 has 8 divisors (see below), whose sum is σ = 5783961784032. Its totient is φ = 1285324840888.
The previous prime is 3213312102157. The next prime is 3213312102257. The reversal of 3213312102230 is 322012133123.
3213312102230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 3213312102196 and 3213312102205.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160665605102 + ... + 160665605121.
It is an arithmetic number, because the mean of its divisors is an integer number (722995223004).
Almost surely, 23213312102230 is an apocalyptic number.
3213312102230 is a deficient number, since it is larger than the sum of its proper divisors (2570649681802).
3213312102230 is a wasteful number, since it uses less digits than its factorization.
3213312102230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 321331210230.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 3213312102230 its reverse (322012133123), we get a palindrome (3535324235353).
The spelling of 3213312102230 in words is "three trillion, two hundred thirteen billion, three hundred twelve million, one hundred two thousand, two hundred thirty".
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