Base | Representation |
---|---|
bin | 11101111011010010… |
… | …001101001110111001 |
3 | 10001221102011201022101 |
4 | 131323102031032321 |
5 | 1011302041011213 |
6 | 22432312423401 |
7 | 2215201124041 |
oct | 357322151671 |
9 | 101842151271 |
10 | 32133141433 |
11 | 1269a358838 |
12 | 62893a7b61 |
13 | 30512b7a73 |
14 | 17ab880721 |
15 | c8103abdd |
hex | 77b48d3b9 |
32133141433 has 2 divisors, whose sum is σ = 32133141434. Its totient is φ = 32133141432.
The previous prime is 32133141409. The next prime is 32133141457. The reversal of 32133141433 is 33414133123.
It is a balanced prime because it is at equal distance from previous prime (32133141409) and next prime (32133141457).
It can be written as a sum of positive squares in only one way, i.e., 20228803984 + 11904337449 = 142228^2 + 109107^2 .
It is a cyclic number.
It is not a de Polignac number, because 32133141433 - 25 = 32133141401 is a prime.
It is not a weakly prime, because it can be changed into another prime (32133141463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16066570716 + 16066570717.
It is an arithmetic number, because the mean of its divisors is an integer number (16066570717).
Almost surely, 232133141433 is an apocalyptic number.
It is an amenable number.
32133141433 is a deficient number, since it is larger than the sum of its proper divisors (1).
32133141433 is an equidigital number, since it uses as much as digits as its factorization.
32133141433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7776, while the sum is 28.
Adding to 32133141433 its reverse (33414133123), we get a palindrome (65547274556).
The spelling of 32133141433 in words is "thirty-two billion, one hundred thirty-three million, one hundred forty-one thousand, four hundred thirty-three".
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