Base | Representation |
---|---|
bin | 1110100111001100111110… |
… | …10000001100010011001111 |
3 | 11012202220201110201020112011 |
4 | 13103212133100030103033 |
5 | 13202433020433212112 |
6 | 152201502220522051 |
7 | 6524361451523233 |
oct | 723463720142317 |
9 | 135686643636464 |
10 | 32133322163407 |
11 | a269735713563 |
12 | 372b7a06b0327 |
13 | 14c120bc1a4ba |
14 | 7d13926105c3 |
15 | 3aacdc5e9aa7 |
hex | 1d399f40c4cf |
32133322163407 has 2 divisors, whose sum is σ = 32133322163408. Its totient is φ = 32133322163406.
The previous prime is 32133322163347. The next prime is 32133322163417. The reversal of 32133322163407 is 70436122333123.
It is a strong prime.
It is an emirp because it is prime and its reverse (70436122333123) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32133322163407 - 231 = 32131174679759 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 32133322163407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32133322163417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16066661081703 + 16066661081704.
It is an arithmetic number, because the mean of its divisors is an integer number (16066661081704).
Almost surely, 232133322163407 is an apocalyptic number.
32133322163407 is a deficient number, since it is larger than the sum of its proper divisors (1).
32133322163407 is an equidigital number, since it uses as much as digits as its factorization.
32133322163407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 40.
The spelling of 32133322163407 in words is "thirty-two trillion, one hundred thirty-three billion, three hundred twenty-two million, one hundred sixty-three thousand, four hundred seven".
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