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32134145330237 is a prime number
BaseRepresentation
bin1110100111001110100000…
…10100010100110000111101
311012202222211211122110010112
413103213100110110300331
513202441212201031422
6152202120024115405
76524421035365436
oct723472024246075
9135688754573115
1032134145330237
11a26a018337a25
12372b990305b65
1314c1310622072
147d142da8a48d
153aad399eaee2
hex1d39d0514c3d

32134145330237 has 2 divisors, whose sum is σ = 32134145330238. Its totient is φ = 32134145330236.

The previous prime is 32134145330197. The next prime is 32134145330281. The reversal of 32134145330237 is 73203354143123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22395713872921 + 9738431457316 = 4732411^2 + 3120646^2 .

It is a cyclic number.

It is not a de Polignac number, because 32134145330237 - 220 = 32134144281661 is a prime.

It is a super-2 number, since 2×321341453302372 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 32134145330194 and 32134145330203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32134145338237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16067072665118 + 16067072665119.

It is an arithmetic number, because the mean of its divisors is an integer number (16067072665119).

Almost surely, 232134145330237 is an apocalyptic number.

It is an amenable number.

32134145330237 is a deficient number, since it is larger than the sum of its proper divisors (1).

32134145330237 is an equidigital number, since it uses as much as digits as its factorization.

32134145330237 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 544320, while the sum is 41.

The spelling of 32134145330237 in words is "thirty-two trillion, one hundred thirty-four billion, one hundred forty-five million, three hundred thirty thousand, two hundred thirty-seven".