Base | Representation |
---|---|
bin | 100100100010011111101001… |
… | …0110101101101001011010011 |
3 | 1120010222120011222122012012121 |
4 | 1021010333102311231023103 |
5 | 314111310140131133021 |
6 | 3055321121334235111 |
7 | 124461254304016336 |
oct | 11104772265551323 |
9 | 1503876158565177 |
10 | 321400235021011 |
11 | 9345408a867593 |
12 | 300696284b5a97 |
13 | 10a44bb1bbc1b3 |
14 | 5951bd659a61d |
15 | 27255572ca741 |
hex | 1244fd2d6d2d3 |
321400235021011 has 2 divisors, whose sum is σ = 321400235021012. Its totient is φ = 321400235021010.
The previous prime is 321400235020987. The next prime is 321400235021069. The reversal of 321400235021011 is 110120532004123.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 321400235021011 - 217 = 321400234889939 is a prime.
It is a super-2 number, since 2×3214002350210112 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (321400235021071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160700117510505 + 160700117510506.
It is an arithmetic number, because the mean of its divisors is an integer number (160700117510506).
Almost surely, 2321400235021011 is an apocalyptic number.
321400235021011 is a deficient number, since it is larger than the sum of its proper divisors (1).
321400235021011 is an equidigital number, since it uses as much as digits as its factorization.
321400235021011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 321400235021011 its reverse (110120532004123), we get a palindrome (431520767025134).
The spelling of 321400235021011 in words is "three hundred twenty-one trillion, four hundred billion, two hundred thirty-five million, twenty-one thousand, eleven".
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