Base | Representation |
---|---|
bin | 1110100111011011011111… |
… | …01000110001001010000011 |
3 | 11012210122211102222122020011 |
4 | 13103231233220301022003 |
5 | 13203044444441442201 |
6 | 152205231254325351 |
7 | 6525055514526013 |
oct | 723555750611203 |
9 | 135718742878204 |
10 | 32141113234051 |
11 | a271a7355a218 |
12 | 37311b5959857 |
13 | 14c1b8109ab83 |
14 | 7d18d124dc43 |
15 | 3ab0e65c5151 |
hex | 1d3b6fa31283 |
32141113234051 has 2 divisors, whose sum is σ = 32141113234052. Its totient is φ = 32141113234050.
The previous prime is 32141113234031. The next prime is 32141113234081. The reversal of 32141113234051 is 15043231114123.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 32141113234051 - 217 = 32141113102979 is a prime.
It is not a weakly prime, because it can be changed into another prime (32141113234031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16070556617025 + 16070556617026.
It is an arithmetic number, because the mean of its divisors is an integer number (16070556617026).
Almost surely, 232141113234051 is an apocalyptic number.
32141113234051 is a deficient number, since it is larger than the sum of its proper divisors (1).
32141113234051 is an equidigital number, since it uses as much as digits as its factorization.
32141113234051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 32141113234051 its reverse (15043231114123), we get a palindrome (47184344348174).
The spelling of 32141113234051 in words is "thirty-two trillion, one hundred forty-one billion, one hundred thirteen million, two hundred thirty-four thousand, fifty-one".
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