Base | Representation |
---|---|
bin | 11101111011110000… |
… | …110001001100010001 |
3 | 10001221222020202011121 |
4 | 131323300301030101 |
5 | 1011311113344131 |
6 | 22433200242241 |
7 | 2215326202354 |
oct | 357360611421 |
9 | 101858222147 |
10 | 32141153041 |
11 | 126a392aaa8 |
12 | 6290010381 |
13 | 3052b6156a |
14 | 17ac96829b |
15 | c81abe911 |
hex | 77bc31311 |
32141153041 has 2 divisors, whose sum is σ = 32141153042. Its totient is φ = 32141153040.
The previous prime is 32141152999. The next prime is 32141153053. The reversal of 32141153041 is 14035114123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20706058816 + 11435094225 = 143896^2 + 106935^2 .
It is a cyclic number.
It is not a de Polignac number, because 32141153041 - 231 = 29993669393 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32141152997 and 32141153015.
It is not a weakly prime, because it can be changed into another prime (32141153441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16070576520 + 16070576521.
It is an arithmetic number, because the mean of its divisors is an integer number (16070576521).
Almost surely, 232141153041 is an apocalyptic number.
It is an amenable number.
32141153041 is a deficient number, since it is larger than the sum of its proper divisors (1).
32141153041 is an equidigital number, since it uses as much as digits as its factorization.
32141153041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 32141153041 its reverse (14035114123), we get a palindrome (46176267164).
The spelling of 32141153041 in words is "thirty-two billion, one hundred forty-one million, one hundred fifty-three thousand, forty-one".
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