Base | Representation |
---|---|
bin | 101110110001011101110… |
… | …110111111001100010011 |
3 | 102101021102211121121010102 |
4 | 232301131312333030103 |
5 | 410130200304424412 |
6 | 10500330544123015 |
7 | 451135061124116 |
oct | 56613566771423 |
9 | 12337384547112 |
10 | 3214210233107 |
11 | 102a158978385 |
12 | 43ab2860646b |
13 | 1a4138b88c23 |
14 | b17d637857d |
15 | 589204c78c2 |
hex | 2ec5ddbf313 |
3214210233107 has 2 divisors, whose sum is σ = 3214210233108. Its totient is φ = 3214210233106.
The previous prime is 3214210233097. The next prime is 3214210233109. The reversal of 3214210233107 is 7013320124123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3214210233107 - 210 = 3214210232083 is a prime.
It is a super-2 number, since 2×32142102331072 (a number of 26 digits) contains 22 as substring.
Together with 3214210233109, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3214210233107.
It is not a weakly prime, because it can be changed into another prime (3214210233109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607105116553 + 1607105116554.
It is an arithmetic number, because the mean of its divisors is an integer number (1607105116554).
Almost surely, 23214210233107 is an apocalyptic number.
3214210233107 is a deficient number, since it is larger than the sum of its proper divisors (1).
3214210233107 is an equidigital number, since it uses as much as digits as its factorization.
3214210233107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
The spelling of 3214210233107 in words is "three trillion, two hundred fourteen billion, two hundred ten million, two hundred thirty-three thousand, one hundred seven".
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