Base | Representation |
---|---|
bin | 101110110001101010011… |
… | …011110110110000000101 |
3 | 102101021222112122001211201 |
4 | 232301222123312300011 |
5 | 410131113313140303 |
6 | 10500403522302501 |
7 | 451143232410205 |
oct | 56615233666005 |
9 | 12337875561751 |
10 | 3214421224453 |
11 | 102a256a8829a |
12 | 43ab871b7a31 |
13 | 1a41707c108a |
14 | b18163bc405 |
15 | 58933ca381d |
hex | 2ec6a6f6c05 |
3214421224453 has 2 divisors, whose sum is σ = 3214421224454. Its totient is φ = 3214421224452.
The previous prime is 3214421224447. The next prime is 3214421224513. The reversal of 3214421224453 is 3544221244123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2369376761284 + 845044463169 = 1539278^2 + 919263^2 .
It is a cyclic number.
It is not a de Polignac number, because 3214421224453 - 217 = 3214421093381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3214421224403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607210612226 + 1607210612227.
It is an arithmetic number, because the mean of its divisors is an integer number (1607210612227).
Almost surely, 23214421224453 is an apocalyptic number.
It is an amenable number.
3214421224453 is a deficient number, since it is larger than the sum of its proper divisors (1).
3214421224453 is an equidigital number, since it uses as much as digits as its factorization.
3214421224453 is an evil number, because the sum of its binary digits is even.
The product of its digits is 184320, while the sum is 37.
Adding to 3214421224453 its reverse (3544221244123), we get a palindrome (6758642468576).
The spelling of 3214421224453 in words is "three trillion, two hundred fourteen billion, four hundred twenty-one million, two hundred twenty-four thousand, four hundred fifty-three".
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