Base | Representation |
---|---|
bin | 1110100111111110111100… |
… | …00001101010111110000101 |
3 | 11012212110221210211212212111 |
4 | 13103333132001222332011 |
5 | 13203402434123002003 |
6 | 152222100002021021 |
7 | 6526331243115205 |
oct | 723773601527605 |
9 | 135773853755774 |
10 | 32160145125253 |
11 | a27a04a567822 |
12 | 3734a27647771 |
13 | 14c38c5023362 |
14 | 7d27b8b2a405 |
15 | 3ab85c35de6d |
hex | 1d3fde06af85 |
32160145125253 has 2 divisors, whose sum is σ = 32160145125254. Its totient is φ = 32160145125252.
The previous prime is 32160145125197. The next prime is 32160145125281. The reversal of 32160145125253 is 35252154106123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32156350811649 + 3794313604 = 5670657^2 + 61598^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32160145125253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32160145195253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16080072562626 + 16080072562627.
It is an arithmetic number, because the mean of its divisors is an integer number (16080072562627).
Almost surely, 232160145125253 is an apocalyptic number.
It is an amenable number.
32160145125253 is a deficient number, since it is larger than the sum of its proper divisors (1).
32160145125253 is an equidigital number, since it uses as much as digits as its factorization.
32160145125253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216000, while the sum is 40.
The spelling of 32160145125253 in words is "thirty-two trillion, one hundred sixty billion, one hundred forty-five million, one hundred twenty-five thousand, two hundred fifty-three".
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