32200140400121 has 2 divisors, whose sum is σ = 32200140400122. Its totient is φ = 32200140400120.

The previous prime is 32200140400069. The next prime is 32200140400123. The reversal of 32200140400121 is 12100404100223.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24910081000000 + 7290059400121 = 4991000^2 + 2700011^2 .

It is a cyclic number.

It is not a de Polignac number, because 32200140400121 - 2²² = 32200136205817 is a prime.

Together with 32200140400123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 32200140400093 and 32200140400102.

It is not a weakly prime, because it can be changed into another prime (32200140400123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16100070200060 + 16100070200061.

It is an arithmetic number, because the mean of its divisors is an integer number (16100070200061).

Almost surely, 2^{32200140400121} is an apocalyptic number.

It is an amenable number.

32200140400121 is a deficient number, since it is larger than the sum of its proper divisors (1).

32200140400121 is an equidigital number, since it uses as much as digits as its factorization.

32200140400121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 32200140400121 its reverse (12100404100223), we get a palindrome (44300544500344).

The spelling of 32200140400121 in words is "thirty-two trillion, two hundred billion, one hundred forty million, four hundred thousand, one hundred twenty-one".