Base | Representation |
---|---|
bin | 101110110111111010010… |
… | …011111011000010001011 |
3 | 102101221022002102202122021 |
4 | 232313322103323002023 |
5 | 410233333241444433 |
6 | 10503433335305311 |
7 | 451501414336525 |
oct | 56677223730213 |
9 | 12357262382567 |
10 | 3221130031243 |
11 | 1032089a23113 |
12 | 440339b1b237 |
13 | 1a499c690937 |
14 | b1c913b8a15 |
15 | 58bc7c4d22d |
hex | 2edfa4fb08b |
3221130031243 has 2 divisors, whose sum is σ = 3221130031244. Its totient is φ = 3221130031242.
The previous prime is 3221130031199. The next prime is 3221130031283. The reversal of 3221130031243 is 3421300311223.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3221130031243 - 221 = 3221127934091 is a prime.
It is a super-2 number, since 2×32211300312432 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3221130031283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1610565015621 + 1610565015622.
It is an arithmetic number, because the mean of its divisors is an integer number (1610565015622).
Almost surely, 23221130031243 is an apocalyptic number.
3221130031243 is a deficient number, since it is larger than the sum of its proper divisors (1).
3221130031243 is an equidigital number, since it uses as much as digits as its factorization.
3221130031243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 3221130031243 its reverse (3421300311223), we get a palindrome (6642430342466).
The spelling of 3221130031243 in words is "three trillion, two hundred twenty-one billion, one hundred thirty million, thirty-one thousand, two hundred forty-three".
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