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322131411142081 is a prime number
BaseRepresentation
bin100100100111110100001000…
…0010101010000010111000001
31120020120110110220111122010021
41021033220100111100113001
5314210300112223021311
63101041043300133441
7124565140444344202
oct11117502025202701
91506513426448107
10322131411142081
11937061897063a2
1230167285997281
1310a98b282a4848
14597935a1c15a9
15273959d37c171
hex124fa105505c1

322131411142081 has 2 divisors, whose sum is σ = 322131411142082. Its totient is φ = 322131411142080.

The previous prime is 322131411141941. The next prime is 322131411142103. The reversal of 322131411142081 is 180241114131223.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 277536274736400 + 44595136405681 = 16659420^2 + 6677959^2 .

It is a cyclic number.

It is not a de Polignac number, because 322131411142081 - 245 = 286947039053249 is a prime.

It is a super-2 number, since 2×3221314111420812 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (322131411182081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161065705571040 + 161065705571041.

It is an arithmetic number, because the mean of its divisors is an integer number (161065705571041).

Almost surely, 2322131411142081 is an apocalyptic number.

It is an amenable number.

322131411142081 is a deficient number, since it is larger than the sum of its proper divisors (1).

322131411142081 is an equidigital number, since it uses as much as digits as its factorization.

322131411142081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 34.

The spelling of 322131411142081 in words is "three hundred twenty-two trillion, one hundred thirty-one billion, four hundred eleven million, one hundred forty-two thousand, eighty-one".