Base | Representation |
---|---|
bin | 1110101001110000110110… |
… | …01010001001100101011001 |
3 | 11020002022210211002122122002 |
4 | 13110320123022021211121 |
5 | 13210403210334100441 |
6 | 152310132213410345 |
7 | 6533624600405522 |
oct | 724703312114531 |
9 | 136068724078562 |
10 | 32221300300121 |
11 | a2a2a82014859 |
12 | 37448543399b5 |
13 | 14c95bcbabb6a |
14 | 7d573aba1849 |
15 | 3ad23b1e5b9b |
hex | 1d4e1b289959 |
32221300300121 has 2 divisors, whose sum is σ = 32221300300122. Its totient is φ = 32221300300120.
The previous prime is 32221300300103. The next prime is 32221300300141. The reversal of 32221300300121 is 12100300312223.
It is an a-pointer prime, because the next prime (32221300300141) can be obtained adding 32221300300121 to its sum of digits (20).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20682812282896 + 11538488017225 = 4547836^2 + 3396835^2 .
It is an emirp because it is prime and its reverse (12100300312223) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32221300300121 - 218 = 32221300037977 is a prime.
It is a super-2 number, since 2×322213003001212 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32221300300093 and 32221300300102.
It is not a weakly prime, because it can be changed into another prime (32221300300141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16110650150060 + 16110650150061.
It is an arithmetic number, because the mean of its divisors is an integer number (16110650150061).
Almost surely, 232221300300121 is an apocalyptic number.
It is an amenable number.
32221300300121 is a deficient number, since it is larger than the sum of its proper divisors (1).
32221300300121 is an equidigital number, since it uses as much as digits as its factorization.
32221300300121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 32221300300121 its reverse (12100300312223), we get a palindrome (44321600612344).
The spelling of 32221300300121 in words is "thirty-two trillion, two hundred twenty-one billion, three hundred million, three hundred thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •