Base | Representation |
---|---|
bin | 101110111001101010100… |
… | …011000010010001011011 |
3 | 102102010011022122120202101 |
4 | 232321222203002101123 |
5 | 410301212314304433 |
6 | 10504344242544231 |
7 | 451566160554562 |
oct | 56715243022133 |
9 | 12363138576671 |
10 | 3223013041243 |
11 | 1032965924426 |
12 | 440784668077 |
13 | 1a4c0c826138 |
14 | b1dcd4dcbd9 |
15 | 58c8820207d |
hex | 2ee6a8c245b |
3223013041243 has 2 divisors, whose sum is σ = 3223013041244. Its totient is φ = 3223013041242.
The previous prime is 3223013041231. The next prime is 3223013041249. The reversal of 3223013041243 is 3421403103223.
It is a happy number.
3223013041243 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3223013041243 - 25 = 3223013041211 is a prime.
It is not a weakly prime, because it can be changed into another prime (3223013041249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1611506520621 + 1611506520622.
It is an arithmetic number, because the mean of its divisors is an integer number (1611506520622).
Almost surely, 23223013041243 is an apocalyptic number.
3223013041243 is a deficient number, since it is larger than the sum of its proper divisors (1).
3223013041243 is an equidigital number, since it uses as much as digits as its factorization.
3223013041243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 3223013041243 its reverse (3421403103223), we get a palindrome (6644416144466).
The spelling of 3223013041243 in words is "three trillion, two hundred twenty-three billion, thirteen million, forty-one thousand, two hundred forty-three".
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