Base | Representation |
---|---|
bin | 1110101010000011010011… |
… | …11100101010101000110011 |
3 | 11020010021101120220021010202 |
4 | 13111001221330222220303 |
5 | 13211034010244201042 |
6 | 152314451525545415 |
7 | 6534425324332634 |
oct | 725015174525063 |
9 | 136107346807122 |
10 | 32231212100147 |
11 | a2a71a8a67925 |
12 | 374675b87526b |
13 | 14ca50c5277a8 |
14 | 7d5ddb32588b |
15 | 3ad61b480632 |
hex | 1d5069f2aa33 |
32231212100147 has 2 divisors, whose sum is σ = 32231212100148. Its totient is φ = 32231212100146.
The previous prime is 32231212100141. The next prime is 32231212100221. The reversal of 32231212100147 is 74100121213223.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 32231212100147 - 218 = 32231211838003 is a prime.
It is not a weakly prime, because it can be changed into another prime (32231212100141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16115606050073 + 16115606050074.
It is an arithmetic number, because the mean of its divisors is an integer number (16115606050074).
Almost surely, 232231212100147 is an apocalyptic number.
32231212100147 is a deficient number, since it is larger than the sum of its proper divisors (1).
32231212100147 is an equidigital number, since it uses as much as digits as its factorization.
32231212100147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 29.
The spelling of 32231212100147 in words is "thirty-two trillion, two hundred thirty-one billion, two hundred twelve million, one hundred thousand, one hundred forty-seven".
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