Base | Representation |
---|---|
bin | 11110000001001000… |
… | …010110111101011011 |
3 | 10002012020201210002212 |
4 | 132001020112331123 |
5 | 1012002143120011 |
6 | 22450134545335 |
7 | 2220501606362 |
oct | 360110267533 |
9 | 102166653085 |
10 | 32231223131 |
11 | 1273a759a98 |
12 | 62b620824b |
13 | 3068709383 |
14 | 17ba8d27d9 |
15 | c8996208b |
hex | 781216f5b |
32231223131 has 2 divisors, whose sum is σ = 32231223132. Its totient is φ = 32231223130.
The previous prime is 32231223091. The next prime is 32231223133. The reversal of 32231223131 is 13132213223.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32231223131 is a prime.
It is a super-2 number, since 2×322312231312 (a number of 22 digits) contains 22 as substring.
Together with 32231223133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 32231223097 and 32231223106.
It is not a weakly prime, because it can be changed into another prime (32231223133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16115611565 + 16115611566.
It is an arithmetic number, because the mean of its divisors is an integer number (16115611566).
Almost surely, 232231223131 is an apocalyptic number.
32231223131 is a deficient number, since it is larger than the sum of its proper divisors (1).
32231223131 is an equidigital number, since it uses as much as digits as its factorization.
32231223131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1296, while the sum is 23.
Adding to 32231223131 its reverse (13132213223), we get a palindrome (45363436354).
The spelling of 32231223131 in words is "thirty-two billion, two hundred thirty-one million, two hundred twenty-three thousand, one hundred thirty-one".
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