Base | Representation |
---|---|
bin | 101111000000010111100… |
… | …110010000101000000011 |
3 | 102102210201222110122001212 |
4 | 233000113212100220003 |
5 | 410410433043442011 |
6 | 10511534422520335 |
7 | 452242435060226 |
oct | 57002746205003 |
9 | 12383658418055 |
10 | 3230211312131 |
11 | 1035a1a08a931 |
12 | 4420532960ab |
13 | 1a57b8c2c31b |
14 | b24b350b5bd |
15 | 5905a13308b |
hex | 2f017990a03 |
3230211312131 has 2 divisors, whose sum is σ = 3230211312132. Its totient is φ = 3230211312130.
The previous prime is 3230211312113. The next prime is 3230211312149. The reversal of 3230211312131 is 1312131120323.
Together with previous prime (3230211312113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a balanced prime because it is at equal distance from previous prime (3230211312113) and next prime (3230211312149).
It is a cyclic number.
It is not a de Polignac number, because 3230211312131 - 214 = 3230211295747 is a prime.
It is a super-2 number, since 2×32302113121312 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 3230211312097 and 3230211312106.
It is not a weakly prime, because it can be changed into another prime (3230211317131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1615105656065 + 1615105656066.
It is an arithmetic number, because the mean of its divisors is an integer number (1615105656066).
Almost surely, 23230211312131 is an apocalyptic number.
3230211312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3230211312131 is an equidigital number, since it uses as much as digits as its factorization.
3230211312131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 3230211312131 its reverse (1312131120323), we get a palindrome (4542342432454).
The spelling of 3230211312131 in words is "three trillion, two hundred thirty billion, two hundred eleven million, three hundred twelve thousand, one hundred thirty-one".
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