Base | Representation |
---|---|
bin | 100100101110111100110011… |
… | …1110010100111101011010111 |
3 | 1120101001012212221221102012202 |
4 | 1021131321213302213223113 |
5 | 314322332121014013142 |
6 | 3103111355214235115 |
7 | 125026036550531423 |
oct | 11135714762475327 |
9 | 1511035787842182 |
10 | 323112131001047 |
11 | 93a540a3485a33 |
12 | 302a5366ab5a9b |
13 | 10b3a460068cbb |
14 | 59b09d3ba9b83 |
15 | 2754d4c16e032 |
hex | 125de67ca7ad7 |
323112131001047 has 2 divisors, whose sum is σ = 323112131001048. Its totient is φ = 323112131001046.
The previous prime is 323112131001019. The next prime is 323112131001119. The reversal of 323112131001047 is 740100131211323.
It is a weak prime.
It is an emirp because it is prime and its reverse (740100131211323) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 323112131001047 - 26 = 323112131000983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (323112131001007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161556065500523 + 161556065500524.
It is an arithmetic number, because the mean of its divisors is an integer number (161556065500524).
Almost surely, 2323112131001047 is an apocalyptic number.
323112131001047 is a deficient number, since it is larger than the sum of its proper divisors (1).
323112131001047 is an equidigital number, since it uses as much as digits as its factorization.
323112131001047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
The spelling of 323112131001047 in words is "three hundred twenty-three trillion, one hundred twelve billion, one hundred thirty-one million, one thousand, forty-seven".
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