Base | Representation |
---|---|
bin | 1110101100011100001101… |
… | …10110011111101000110111 |
3 | 11020102010021112101202220011 |
4 | 13112032012312133220313 |
5 | 13213410120124300434 |
6 | 152420305320321051 |
7 | 6543362506015045 |
oct | 726160666375067 |
9 | 136363245352804 |
10 | 32313301400119 |
11 | a328aa32639a3 |
12 | 375a64b313187 |
13 | 150519247207c |
14 | 7d9d87763395 |
15 | 3b08230a0e64 |
hex | 1d6386d9fa37 |
32313301400119 has 2 divisors, whose sum is σ = 32313301400120. Its totient is φ = 32313301400118.
The previous prime is 32313301400111. The next prime is 32313301400123. The reversal of 32313301400119 is 91100410331323.
It is a strong prime.
It is an emirp because it is prime and its reverse (91100410331323) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32313301400119 - 23 = 32313301400111 is a prime.
It is a super-2 number, since 2×323133014001192 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32313301400111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16156650700059 + 16156650700060.
It is an arithmetic number, because the mean of its divisors is an integer number (16156650700060).
Almost surely, 232313301400119 is an apocalyptic number.
32313301400119 is a deficient number, since it is larger than the sum of its proper divisors (1).
32313301400119 is an equidigital number, since it uses as much as digits as its factorization.
32313301400119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 31.
The spelling of 32313301400119 in words is "thirty-two trillion, three hundred thirteen billion, three hundred one million, four hundred thousand, one hundred nineteen".
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