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32322313121981 is a prime number
BaseRepresentation
bin1110101100101100111111…
…11111011111000010111101
311020102222112120112200021112
413112112133333133002331
513214032044124400411
6152424355441011405
76544132023256451
oct726263777370275
9136388476480245
1032322313121981
11a3318a8130a13
123760345323b65
131505c9a49787c
147da5a054a661
153b0b9e2e5b8b
hex1d659ffdf0bd

32322313121981 has 2 divisors, whose sum is σ = 32322313121982. Its totient is φ = 32322313121980.

The previous prime is 32322313121909. The next prime is 32322313122023. The reversal of 32322313121981 is 18912131322323.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27757787696356 + 4564525425625 = 5268566^2 + 2136475^2 .

It is a cyclic number.

It is not a de Polignac number, because 32322313121981 - 234 = 32305133252797 is a prime.

It is a super-2 number, since 2×323223131219812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32322313121081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16161156560990 + 16161156560991.

It is an arithmetic number, because the mean of its divisors is an integer number (16161156560991).

Almost surely, 232322313121981 is an apocalyptic number.

It is an amenable number.

32322313121981 is a deficient number, since it is larger than the sum of its proper divisors (1).

32322313121981 is an equidigital number, since it uses as much as digits as its factorization.

32322313121981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 93312, while the sum is 41.

The spelling of 32322313121981 in words is "thirty-two trillion, three hundred twenty-two billion, three hundred thirteen million, one hundred twenty-one thousand, nine hundred eighty-one".