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3233011313113 is a prime number
BaseRepresentation
bin101111000010111110011…
…111011010100111011001
3102110001222010011102022221
4233002332133122213121
5410432201344004423
610513120324344041
7452402014511341
oct57027637324731
912401863142287
103233011313113
11103712666902a
124426b4b45021
131a5b44059b3a
14b269b331d21
1559170d6ce5d
hex2f0be7da9d9

3233011313113 has 2 divisors, whose sum is σ = 3233011313114. Its totient is φ = 3233011313112.

The previous prime is 3233011313099. The next prime is 3233011313167. The reversal of 3233011313113 is 3113131103323.

3233011313113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3118907877849 + 114103435264 = 1766043^2 + 337792^2 .

It is a cyclic number.

It is not a de Polignac number, because 3233011313113 - 213 = 3233011304921 is a prime.

It is not a weakly prime, because it can be changed into another prime (3233011317113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1616505656556 + 1616505656557.

It is an arithmetic number, because the mean of its divisors is an integer number (1616505656557).

Almost surely, 23233011313113 is an apocalyptic number.

It is an amenable number.

3233011313113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3233011313113 is an equidigital number, since it uses as much as digits as its factorization.

3233011313113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 3233011313113 its reverse (3113131103323), we get a palindrome (6346142416436).

The spelling of 3233011313113 in words is "three trillion, two hundred thirty-three billion, eleven million, three hundred thirteen thousand, one hundred thirteen".