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3233245512131 is a prime number
BaseRepresentation
bin101111000011001100011…
…100110100000111000011
3102110002120102211221222122
4233003030130310013003
5410433141322342011
610513155452154455
7452410560253325
oct57031434640703
912402512757878
103233245512131
11103723688a238
1244275b468a2b
131a5b8072943b
14b26c0497615
15591866d03db
hex2f0cc7341c3

3233245512131 has 2 divisors, whose sum is σ = 3233245512132. Its totient is φ = 3233245512130.

The previous prime is 3233245512121. The next prime is 3233245512209. The reversal of 3233245512131 is 1312155423323.

It is a weak prime.

It is an emirp because it is prime and its reverse (1312155423323) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3233245512131 - 230 = 3232171770307 is a prime.

It is a super-2 number, since 2×32332455121312 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 3233245512091 and 3233245512100.

It is not a weakly prime, because it can be changed into another prime (3233245512121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1616622756065 + 1616622756066.

It is an arithmetic number, because the mean of its divisors is an integer number (1616622756066).

Almost surely, 23233245512131 is an apocalyptic number.

3233245512131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3233245512131 is an equidigital number, since it uses as much as digits as its factorization.

3233245512131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 64800, while the sum is 35.

The spelling of 3233245512131 in words is "three trillion, two hundred thirty-three billion, two hundred forty-five million, five hundred twelve thousand, one hundred thirty-one".